Organic chemistry (3.3)Organic analysis - mass spectrometry and infrared spectroscopy (3.3.6)

Organic analysis - mass spectrometry and infrared spectroscopy (3.3.6)

How mass spectrometry, infrared spectroscopy and test tube analysis can be used to identify organic molecules.
11 min

The electrophilic addition of bromine to alkenes is used as a test for unsaturation.

is orange and bromoalkanes are colourless. When the substances are mixed they react and as the reaction progresses the orange colour fades.

Illustration of the Bromine water test for saturation. A dropper is shown dispensing orange bromine water above three test tubes. The first tube contains a chemical sample, the second tube shows a saturated solution (no double bonds) with an orange color, and the third tube shows an unsaturated solution (with double bonds) that remains blue.

To complete the test, bromine water is shaken with a test sample, and the results are observed.

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Fehling’s solution and Benedict’s solution are used to identify aldehydes.

Both solutions rely upon the oxidation of the aldehyde to a carboxylic acid salt, by a solution of a blue complex of copper(II) ions, which is subsequently reduced to a brick-red precipitate of copper(I) oxide in alkaline conditions.

A step-by-step illustration of a chemical test using Benedict's solution. The first step shows a test tube with about 2 cm³ of test solution. The second step indicates adding an equal amount of Benedict's solution, followed by heating in a water bath. The final step depicts the resulting brick-red precipitate.

The ligands on the copper complex in Fehling’s and Benedict’s solutions are different but both exhibit a change from a blue solution to a brick-red precipitate on heating with a reducing agent (e.g. an aldehyde).

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Tollens’ reagent contains aqueous silver nitrate, dissolved in ammonia forming the complex ion .

Aldehydes are easily oxidised to carboxylate ions in basic conditions.

Tollens’ reagent acts as an oxidising agent. It is reduced, causing silver ions () to be reduced to metallic silver ( ).

This results in a silver mirror forming on the inside of the test tube, indicating the presence of an aldehyde.

A diagram illustrating a chemical reaction where a colourless solution of silver diamine complex (Ag(NH3)2+) transforms into a silver mirror (Ag) in a test tube.

Ketones cannot be oxidised as they lack a hydrogen atom on the carbonyl atom. Therefore ketones do not react with Tollens’ reagent and no silver mirror forms.

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Felling’s test and Tollens’ test can be used to distinguish between aldehydes and ketones. Both tests give a positive result for an aldehyde but not for a ketone.

A comparison table showing the results of Fehling's test and Tollens' test for aldehydes and ketones. Fehling's test indicates that aldehydes produce a brick-red Cu2O precipitate, while ketones show no reaction. Tollens' test indicates that aldehydes form a silver mirror, while ketones also show no reaction.

They are also useful for distinguishing primary and secondary alcohols. The alcohols can be oxidised and the products distilled as they are formed then tested. Only primary alcohols produce aldehydes that give a positive result.

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Alcohols can be oxidised to carbonyl compounds during redox reactions with oxidising agents.

Acidified potassium dichromate VI () is commonly used in the oxidation of alcohols.

Dichromate ions, , turn from orange to green as they are reduced to . The oxidation state of chromium reduces from +6 to +3.

Two laboratory flasks side by side. The left flask contains a yellow solution labeled with 'Cr2O7^2-' indicating chromium in the +6 oxidation state. The right flask contains a green solution labeled with 'Cr^3+' indicating chromium in the +3 oxidation state, with both flasks emitting vapor.
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When oxidised, primary alcohols form aldehydes first before further oxidation to carboxylic acids.

A diagram illustrating the oxidation of a primary alcohol. The first structure shows a primary alcohol with an -OH group attached to a carbon atom. The second structure, labeled 'Aldehyde,' shows the alcohol oxidized to an aldehyde with a carbonyl group (C=O). The third structure, labeled 'Carboxylic acid,' shows further oxidation to a carboxylic acid, which retains the carbonyl group and adds an -OH group.
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Secondary alcohols are oxidised to form ketones.

Diagram illustrating the conversion of a secondary alcohol to a ketone. The structure on the left shows a secondary alcohol with an -OH group, while the structure on the right depicts the resulting ketone after oxidation, indicated by the [O] arrow.
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Tertiary alcohols CANNOT be oxidised as they do not have a proton on the carbon bearing the group.

Diagram illustrating a tertiary alcohol with the hydroxyl group (OH) attached to a carbon atom (C) that is connected to three other groups (R, R', R'). The diagram indicates that when oxidized ([O]), there is no reaction.
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Organic molecules in a mass spectrometer are vapourised then undergo ionisation, with the loss of an electron from one of the covalent bonds.

This can be represented as:

is the molecular ion, it represents the whole molecule minus one electron.

The singly charged molecular ion peak, , has an m/z equal to the molecule’s relative molecular mass ().

The molecular ion peak has the highest m/z value and is located on the far right of the mass spectrum.

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Mass spectra of organic molecules will exhibit a tiny peak at 1 mass unit greater than the molecular ion.

This is called the M+1 peak and is caused by the presence of the carbon-13 isotope which comprises of all carbon atoms.

A mass spectrum graph displaying relative intensity on the vertical axis and mass-to-charge ratio (m/z) on the horizontal axis. The spectrum shows a prominent peak at m/z 58 labeled as M+ and a smaller peak at m/z 59 labeled as M+1. The compound represented is CH3COCH3.

The of propanone, , is 58.

In the spectrum of propanone, the molecular ion peak, , is at 58 and a smaller M+1 peak at 59 shows the proportion of propanone featuring carbon-13.

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Molecular ions formed during ionisation are positively charged radicals and are generally unstable.

They split to form a radical and a cation; this is called fragmentation.

A diagram illustrating the mass spectrum fragmentation of a chemical compound. The structure shows a carbon chain with functional groups, and arrows indicate the formation of fragment ions and radicals. Key mass-to-charge ratios (m/z) are labeled, with annotations explaining that radicals do not appear on the mass spectrum while fragment ions provide structural information.

The cationic molecular fragment ions can be seen in the mass spectrum.

All fragment ions will have lower molar mass than the molecular ion, .

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Some fragment ions may be formed more frequently.

A table displaying mass-to-charge ratios (m/z) and corresponding fragment ions. The table lists fragment ions for various groups, including methyl, ethyl, aldehyde, acyl, propyl, isopropyl, and phenyl, along with their respective m/z values.

m/z 29 and m/z 43 are commonly used in exams due to the variety of fragments they can be associated with.

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The molecular ion peak, , represents the relative formula mass () of the whole molecule.

High-resolution mass spectrometry (HRMS) can measure this peak to a high degree of precision, such as four or more decimal places, providing an exact mass.

By comparing the exact recorded mass to the sum of the masses of the constituent atoms, chemists can calculate the possible combinations of atoms that could make up the molecule. This gives the molecular formula.

A table displaying isotopes and their precise atomic masses. The isotopes listed are Hydrogen-1 (1H) with a mass of 1.0078, Carbon-12 (12C) with a mass of 12.0000, Nitrogen-14 (14N) with a mass of 14.0031, and Oxygen-16 (16O) with a mass of 15.9949.

Propane () and ethanal () have the same relative formula mass to the nearest whole number, 44.

On a high-resolution mass spectrum the molecules are distinguishable by the peak; gives a molecular ion peak at m/z = 44.0624 while gives a molecular ion peak at m/z = 44.0261.

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Infrared (IR) spectroscopy is an analytical technique that enables chemists to identify vibrations from covalent bonds within molecules.

This is useful for working out the characteristic functional groups within organic compounds.

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Vibrational movement of covalent bonds exists as two main types: bond stretching, and bond bending.

Illustration showing molecular vibrations: on the left, a carbon dioxide molecule demonstrating stretching; in the center, a water molecule illustrating bending; and on the right, another stretching representation of a water molecule.

Each vibration is associated with a particular wavelength and frequency. When exposed to IR radiation the bonds absorb radiation at their characteristic wavelength and vibrate more vigorously.

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IR radiation is only absorbed by covalent bonds that have a permanent dipole, such as , and . The dipole does not need to be large but it must exist.

Vibrations from bonds without a permanent dipole, such as or , are invisible in IR spectrometry.

Non-polar molecules containing polar bonds, such as linear , have a combination of IR visible and invisible vibrating modes dependent on symmetry.

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Vibrational absorptions are seen where there are inverted peaks; in these regions there is a reduction in the radiation able to pass through the sample.
The deeper the peak the more radiation has been absorbed. These prominent peaks are most distinctive, and therefore most useful in characterisation.

The IR spectrum for propanal is shown below.

A graph displaying transmittance percentage on the vertical axis and wavenumber in cm⁻¹ on the horizontal axis. The curve shows variations in transmittance across different wavenumbers, with peaks and troughs indicating absorption characteristics.

It has a prominent peak around 1700 cm-1 which is characteristic of the carbonyl functional group present in .

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Different functional groups present in an organic compound can be identified from their IR stretching peaks.

A basic outline of the main groups and their characteristics absorption frequencies in IR is as shown below:

A graph displaying transmittance percentage on the vertical axis and wavenumber in cm⁻¹ on the horizontal axis. The graph is divided into regions for single bonds, triple bonds, double bonds, and a fingerprint region. It lists specific bonds like O–H, N–H, C–H, C≡N, C≡C, C=O, and C=C, with a note about using a database to match spectra.

You will not be required to memorise this data.

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The presence of the bond stretching is easy to locate, though of limited use in distinguishing one organic compound from another.

A graph displaying transmittance percentage on the vertical axis and wavenumber in cm⁻¹ on the horizontal axis. The graph shows a dip in transmittance around the wavenumber range of 2850-3100 cm⁻¹, indicating the presence of C-H bonds in alkyl, alkene, and arene compounds.
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A strong, broad peak is characteristic of bond stretching in alcohols.

This notable peak is located just to the left of the landmark bond peak and is very popular in exam questions.

A graph showing transmittance percentage on the vertical axis and wavenumber in cm⁻¹ on the horizontal axis. The graph features a curve indicating transmittance levels, with notable dips corresponding to O–H bonds in alcohols and phenols between 3200 and 3600 cm⁻¹, and C–H bonds indicated.

Be careful as the bond, although a weaker signal, is located in the same region as a bond.

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The bond stretching, found in aldehydes, ketones, and other carbonyl-containing compounds is very easy to recognise as a strong narrow peak, almost in the middle of the spectrum around .

A graph showing transmittance percentage on the vertical axis and wavenumber in cm-1 on the horizontal axis. The graph features a dip indicating the presence of C=O functional groups in various organic compounds, with a specific range noted between 1630-1820 cm-1.

More details are required to fully identify the functional group.

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The spectrum for the carboxylic acid group contains a stretch at and the very broad and strong peak of the group in carboxylic acids from .

Its breadth is due to hydrogen bonding between carboxylic acid groups causing variation in the vibration.

A graph depicting transmittance percentage on the vertical axis and wavenumber in cm⁻¹ on the horizontal axis. The graph shows peaks and troughs indicating the presence of functional groups, specifically C=O in carboxylic acids between 1630-1820 cm⁻¹ and O-H in carboxylic acids between 2500-3300 cm⁻¹, with a broad peak. The C-H bond is also indicated on the graph.

The carboxylic acid peak overlaps the bond peak, which can often be seen just below the broad carboxylic acid peak.

If there was a narrow peak and a peak this would indicate an alcohol and a carbonyl were present, not a carboxylic acid.

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In amine’s, bond stretching appears as a characteristic peak in the IR spectrum, typically between .

This peak is often medium in intensity and can be either sharp or broad, depending on whether the amine is primary or secondary. It is significantly less intense than the of an alcohol, but is in the same region.

A graph showing the transmittance percentage of a primary amine as a function of wavenumber in cm⁻¹. The y-axis represents transmittance from 0% to 100%, while the x-axis displays wavenumbers ranging from 4000 to 500 cm⁻¹. Notable features include a dip in transmittance around 3000 cm⁻¹, indicating the presence of an amine functional group.
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Most exam questions present an infrared spectrum and ask for the identity of the compound, or some structural features, deducible from the data.

Using the supplied data sheet spectroscopy table is essential here but a good understanding of the key peaks below will speed up your analysis.

A graph displaying transmittance percentage on the vertical axis and wavenumber in cm⁻¹ on the horizontal axis. The graph shows several peaks and troughs, indicating the presence of functional groups such as O-H for alcohol/phenol and carboxylic acid, C-H for hydrocarbons, and C=O for carbonyl. Additional annotations highlight regions for ester, alcohol, and carboxylic acid.

IR spectra are most commonly assessed in combination with other techniques such as nuclear magnetic resonance (NMR) and mass spectrometry.

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The absence of particular peaks from a spectrum can also help to confirm the identity of a functional group.

A commonly tested scenario is analysis of an alcohol oxidation. This involves distinguishing unreacted alcohol, aldehydes, ketones, and/or carboxylic acids.

Here we need to look for the absence, or presence, of the carboxylic acid’s broad peak. Likewise, the absence or presence of an alcohol peak. This will give a definitive answer on the presence of a carboxylic acid or an unreacted alcohol.

Aldehydes and ketones require additional data to identify. The IR spectra could be combined with NMR, mass spectrometry or qualitative tests such as using the Tollens reagent.

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The region comprising a series of many overlapping peaks, to the right hand side of the IR spectrum, from 1500 – 500 cm-1, is known as the fingerprint region.

Two similar molecules, such as structural isomers, propan-1-ol and propan-2-ol, will produce a similar spectra in the functional group region, however, there will always be significant differences in the fingerprint region.

Comparison of the IR spectra of propan-1-ol and propan-2-ol. The upper graph shows the spectrum for propan-1-ol, while the lower graph displays the spectrum for propan-2-ol. Both graphs plot transmittance percentage against wavenumber (cm⁻¹), with insets highlighting visible differences in the fingerprint region.

The fingerprint region provides a set of peaks that is uniquely characteristic of each compound, meaning it serves as a molecular fingerprint that allows identification of a molecule.

By comparing the fingerprint region of an unknown compound to reference spectra, chemists can accurately identify the compound. The process is called fingerprinting.

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Question walkthrough

Combined spectroscopic analysis

Using mass spectrometry, IR spectrometry and elemental analysis in tandem

The most abundant atmospheric gases, and , show no change in dipole moment and do not interact with infrared radiation.

Illustration of three chemical compounds: Water (H2O) with two hydrogen atoms (green) bonded to one oxygen atom (purple), Carbon dioxide (CO2) with one carbon atom (red) bonded to two oxygen atoms (purple), and Methane (CH4) with one carbon atom (red) bonded to four hydrogen atoms (green).

Some atmospheric gases do absorb IR radiation; these include , , and .

These gases are known as greenhouse gases.

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When solar radiation enters the earth’s atmosphere, it is absorbed by the earth’s surface and oceans before being re-emitted at longer wavelengths, mainly as IR radiation.

An illustration depicting the Earth's atmosphere with sunlight entering from the sun, represented by wavy lines. Various molecules are shown in the atmosphere, interacting with sunlight and emitting infrared radiation, indicated by red arrows. The Earth is visible at the bottom of the image.

The increased presence of atmospheric gases that interact with IR radiation cause a greater proportion of this radiation to be held within the atmosphere rather than entering space. This causes heating of the atmosphere, and scientists refer to this as global warming.

Human activity, most notably the extraction and combustion of fossil fuels, have led to much greater levels of atmospheric in recent history.

Increased reliance on renewable energy sources with reduced production such as nuclear, wind, wave, solar, and tidal power, alongside using carbon capture and storage methods should slow greenhouse gas production and global warming.

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